Optimal. Leaf size=97 \[ -\frac {x^{-2+m}}{2 (2-m)}-2^{-m} b^2 e^{2 i a} x^m (-i b x)^{-m} \Gamma (-2+m,-2 i b x)-2^{-m} b^2 e^{-2 i a} x^m (i b x)^{-m} \Gamma (-2+m,2 i b x) \]
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Rubi [A]
time = 0.11, antiderivative size = 97, normalized size of antiderivative = 1.00, number of steps
used = 5, number of rules used = 3, integrand size = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.214, Rules used = {3393, 3388,
2212} \begin {gather*} -e^{2 i a} b^2 2^{-m} x^m (-i b x)^{-m} \text {Gamma}(m-2,-2 i b x)-e^{-2 i a} b^2 2^{-m} x^m (i b x)^{-m} \text {Gamma}(m-2,2 i b x)-\frac {x^{m-2}}{2 (2-m)} \end {gather*}
Antiderivative was successfully verified.
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Rule 2212
Rule 3388
Rule 3393
Rubi steps
\begin {align*} \int x^{-3+m} \sin ^2(a+b x) \, dx &=\int \left (\frac {x^{-3+m}}{2}-\frac {1}{2} x^{-3+m} \cos (2 a+2 b x)\right ) \, dx\\ &=-\frac {x^{-2+m}}{2 (2-m)}-\frac {1}{2} \int x^{-3+m} \cos (2 a+2 b x) \, dx\\ &=-\frac {x^{-2+m}}{2 (2-m)}-\frac {1}{4} \int e^{-i (2 a+2 b x)} x^{-3+m} \, dx-\frac {1}{4} \int e^{i (2 a+2 b x)} x^{-3+m} \, dx\\ &=-\frac {x^{-2+m}}{2 (2-m)}-2^{-m} b^2 e^{2 i a} x^m (-i b x)^{-m} \Gamma (-2+m,-2 i b x)-2^{-m} b^2 e^{-2 i a} x^m (i b x)^{-m} \Gamma (-2+m,2 i b x)\\ \end {align*}
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Mathematica [A]
time = 0.26, size = 121, normalized size = 1.25 \begin {gather*} \frac {2^{-1-m} x^{-2+m} \left (b^2 x^2\right )^{-m} \left (2^m \left (b^2 x^2\right )^m-2 b^2 (-2+m) x^2 (-i b x)^m \Gamma (-2+m,2 i b x) (\cos (a)-i \sin (a))^2+2 (-2+m) (i b x)^{2+m} \Gamma (-2+m,-2 i b x) (\cos (2 a)+i \sin (2 a))\right )}{-2+m} \end {gather*}
Antiderivative was successfully verified.
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Maple [F]
time = 0.04, size = 0, normalized size = 0.00 \[\int x^{m -3} \left (\sin ^{2}\left (b x +a \right )\right )\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.09, size = 77, normalized size = 0.79 \begin {gather*} \frac {4 \, b x x^{m - 3} + {\left (-i \, m + 2 i\right )} e^{\left (-{\left (m - 3\right )} \log \left (2 i \, b\right ) - 2 i \, a\right )} \Gamma \left (m - 2, 2 i \, b x\right ) + {\left (i \, m - 2 i\right )} e^{\left (-{\left (m - 3\right )} \log \left (-2 i \, b\right ) + 2 i \, a\right )} \Gamma \left (m - 2, -2 i \, b x\right )}{8 \, {\left (b m - 2 \, b\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int x^{m - 3} \sin ^{2}{\left (a + b x \right )}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int x^{m-3}\,{\sin \left (a+b\,x\right )}^2 \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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